10x^2-x(x+2)+8x+1=0

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Solution for 10x^2-x(x+2)+8x+1=0 equation: 



10x^2-x(x+2)+8x+1=0

We add all the numbers together, and all the variables

10x^2+8x-x(x+2)+1=0

We multiply parentheses

10x^2-x^2+8x-2x+1=0

We add all the numbers together, and all the variables

9x^2+6x+1=0

a = 9; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·9·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{18}=-1/3$

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